Modular Exponentiation 3^37mod43

Solve 337 mod 43 using: Modular exponentiation n is our exponent = 37 y = 1 and u 3 mod 43 = 3 See here Since 37 is odd, calculate (y)(u) mod p (y)(u) mod p = (1)(3) mod 43 (y)(u) mod p = 3 mod 43

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Enter Modular Exponentiation

Solve 337 mod 43 using:

Modular exponentiation

Build an algorithm:

n is our exponent = 37

y = 1 and u ≡ 3 mod 43 = 3

See here

n = 37 is odd

Since 37 is odd, calculate (y)(u) mod p

(y)(u) mod p = (1)(3) mod 43

(y)(u) mod p = 3 mod 43

3 mod 43 = 3
Reset y to this value

Determine u2 mod p

u2 mod p = 32 mod 43

u2 mod p = 9 mod 43

9 mod 43 = 9
Reset u to this value

Cut n in half and take the integer

37 ÷ 2 = 18

n = 18 is even

Since 18 is even, we keep y = 3

Determine u2 mod p

u2 mod p = 92 mod 43

u2 mod p = 81 mod 43

81 mod 43 = 38
Reset u to this value

Cut n in half and take the integer

18 ÷ 2 = 9

n = 9 is odd

Since 9 is odd, calculate (y)(u) mod p

(y)(u) mod p = (3)(38) mod 43

(y)(u) mod p = 114 mod 43

114 mod 43 = 28
Reset y to this value

Determine u2 mod p

u2 mod p = 382 mod 43

u2 mod p = 1444 mod 43

1444 mod 43 = 25
Reset u to this value

Cut n in half and take the integer

9 ÷ 2 = 4

n = 4 is even

Since 4 is even, we keep y = 28

Determine u2 mod p

u2 mod p = 252 mod 43

u2 mod p = 625 mod 43

625 mod 43 = 23
Reset u to this value

Cut n in half and take the integer

4 ÷ 2 = 2

n = 2 is even

Since 2 is even, we keep y = 28

Determine u2 mod p

u2 mod p = 232 mod 43

u2 mod p = 529 mod 43

529 mod 43 = 13
Reset u to this value

Cut n in half and take the integer

2 ÷ 2 = 1

n = 1 is odd

Since 1 is odd, calculate (y)(u) mod p

(y)(u) mod p = (28)(13) mod 43

(y)(u) mod p = 364 mod 43

364 mod 43 = 20
Reset y to this value

Determine u2 mod p

u2 mod p = 132 mod 43

u2 mod p = 169 mod 43

169 mod 43 = 40
Reset u to this value

Cut n in half and take the integer

1 ÷ 2 = 0

Because n = 0, we stop

We have our answer

Final Answer

337 mod 43 ≡ 20

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What is the Answer?

337 mod 43 ≡ 20

How does the Modular Exponentiation and Successive Squaring Calculator work?

Free Modular Exponentiation and Successive Squaring Calculator - Solves xn mod p using the following methods:
* Modular Exponentiation
* Successive Squaring
This calculator has 1 input.

What 1 formula is used for the Modular Exponentiation and Successive Squaring Calculator?

Successive Squaring I = number of digits in binary form of n. Run this many loops of a2 mod p

For more math formulas, check out our Formula Dossier

What 6 concepts are covered in the Modular Exponentiation and Successive Squaring Calculator?

exponentThe power to raise a numberintegera whole number; a number that is not a fraction
...,-5,-4,-3,-2,-1,0,1,2,3,4,5,...modular exponentiationthe remainder when an integer b (the base) is raised to the power e (the exponent), and divided by a positive integer m (the modulus)modulusthe remainder of a division, after one number is divided by another.
a mod bremainderThe portion of a division operation leftover after dividing two integerssuccessive squaringan algorithm to compute in a finite field

Example calculations for the Modular Exponentiation and Successive Squaring Calculator

Modular Exponentiation and Successive Squaring Calculator Video


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